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``solve: sqrt (r - 1)
When I solve the inquality 2x^2 - 6 < 0,
I get x < + or - sqrt(3) So how do I write the solution? Is it (+sqrt(3),-sqrt(3)) or
0 answers
asked by
Jen
1,284 views
So I am supposed to solve this without using a calculator: Sqrt[20]/10 - Sqrt[10]/Sqrt[32] - Sqrt[0.3125] + Sqrt[3 + 1/5]
You can
2 answers
asked by
Mr.AMG
830 views
Solve in the exact form.
(sqrt of 4x+1)+(sqrt of x+1)=2 Someone showed me to do this next: Square both sides..so.. 4x+1+2((sqrt
4 answers
asked by
Gingie
1,152 views
Could someone show me how to solve these problems step by step....
I am confused on how to fully break this down to simpliest
1 answer
asked by
Reggie
1,352 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.
sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
1 answer
asked by
Alexa
3,199 views
I hope I am writing this down right.. I am trying to do some practice questions to learn
10^5 (sqrt)2y - 4^5 (sqrt)2y I am trying
2 answers
asked by
Cassie
683 views
Solve the quadratic equation 6x^2-3x+6=0. Which of the following expresses its solutions in the form a± bi ? (1 point) 1/4 ±
1 answer
27 views
Please look at my work below:
Solve the initial-value problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/-
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asked by
COFFEE
887 views
sqrt 6 * sqrt 8
also sqrt 7 * sqrt 5 6.92820323 and 5.916079783 So you can see the steps — sqrt 6 * sqrt 8 = sqrt 48 sqrt 7 *
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asked by
Tina
723 views
i am really trying is this correct.
solve: 5(x-2)^2 = 3 MY ANSWER THAT I GOT IS: X = 2 +- (SQRT (3) )/(5) no. 5(x-2)^2 = 3
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asked by
jasmine20
1,234 views