[sinxcosx/(1+cosx(]-[sinx/(1-cosx)]= -(cotxcosx+cscx)

[sinxcosx/(1+cosx(]-[sinx/(1-cosx)]= -(cotxcosx+cscx)
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2. asked by Christie
3. 503 views
1) evaluate without a calculator: a)sin(3.14/4) b) cos(-3(3.14)/4) c) tan(4(3.14)/3) d) arccos(- square root of three/2) e)
1. 1 answer
2. asked by Emily
3. 1,494 views
Prove the following identity:1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
1. 1 answer
2. asked by Heather
3. 788 views
Verify the identity .(cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant help you (cscX-cotX)=1/sinX - cosX/sinX = (1-cosX)/sinX If
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2. asked by Rose
3. 722 views
Proving identity(sinx+tanx)/(cosx+1)=tanx RS: (sinx+(sinx/cosx))/(cosx+1) ((sinxcosx/cosx)+(sinx/cosx))x 1/(cosx+1)
1. 1 answer
2. asked by sh
3. 626 views
Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
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2. asked by Anonymous
3. 1,348 views
Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1. 4 answers
2. asked by Anonymous
3. 1,949 views
Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1. 1 answer
2. asked by Anonymous
3. 1,073 views
Which of the following are trigonometric identities?(Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x
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2. asked by Jill
3. 4,795 views
I can't seem to prove these trig identities and would really appreciate help:1. cosx + 1/sin^3x = cscx/1 - cosx I changed the 1:
1. 1 answer
2. asked by Heather
3. 1,281 views