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[Cos70°- cos60°]÷[sin 70°- sin50°]= -√3

  1. [Cos70°- cos60°]÷[sin 70°- sin50°]= -√3
    1. answers icon 1 answer
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  2. (Cos70-cos50)÷(sin70-sin50) =-√3
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  3. If 𝑎 = sin70°,𝑏 = cos70°,𝑐 = tan70°,𝑑 = 1/cos70° , order them from the largest to the smallest.
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    2. Anonymous asked by Anonymous
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  4. the triangle CDE, m<D=90 degrees, m<C=50 degrees, and ED=23. Which equation could be used to find CE?1. sin50=CE/23 2.
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    2. B8 asked by B8
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  5. Find the exact value of: sin60-cos60.do I just type sin60-cos60 in my calculator? = .37
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    2. Jon asked by Jon
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  6. A player kicks a football with an initial velocity of 3.00 m/s at an angle of 60.0 above the horizontal. What is the horizontal
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    2. Jon asked by Jon
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  7. A player kicks a football with an initial velocity of 3.00 m/s at an angle of 60.0 above the horizontal. What is the horizontal
    1. answers icon 1 answer
    2. Jon asked by Jon
    3. views icon 739 views
  8. Prove that, sin60° cos60° - sin30° cos60°=sin30° ?
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    2. Joackim Patrick asked by Joackim Patrick
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  9. Prove thatsin50° - sin70° + sin10° = 0
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    2. Kewal asked by Kewal
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  10. Show that sin70°+sin50°= √3cos0°
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    2. views icon 51 views