(sinx-cosx)^2=sin2x

Verify the identity:tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx
1. 0 answers
2. asked by Ashley
3. 1,244 views
Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1. 4 answers
2. asked by Anonymous
3. 1,948 views
Simplify #1:cscx(sin^2x+cos^2xtanx)/sinx+cosx = cscx((1)tanx)/sinx+cosx = cscxtanx/sinx+cosx Is the correct answer
1. 1 answer
2. asked by Anonymous
3. 1,347 views
Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1. 1 answer
2. asked by Anonymous
3. 1,071 views
Hi, I need a bit of help with verifying identities. The problems are as follows:sinx+cosx/cotx+1=sinx sin2x/sin -
1. 2 answers
2. asked by Retrograde
3. 629 views
sin2x+cosx=0 , [-180,180)= 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2=360-90 x2=270 270 doesn't fit in
1. 1 answer
2. asked by Anonymous
3. 913 views
Prove the following functions:(sinx+sin2x)/(1+cosx+cos2x)=tan x (cos3x/sinx)+(sin3x/cosx)=2cot2x tan2x=(2/cotx-tanx) theses are
1. 2 answers
2. asked by jared
3. 1,091 views
hey, i would really appreciate some help solving for x when:sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
1. 0 answers
2. asked by elle
3. 715 views
prove identitySin2x - sinx/cosx + cos2x= sinx/cosx + 1
1. 1 answer
2. asked by Matthew
3. 1,177 views
how does this work?(Sin2x+cos2x+2sin²x)/(sinx+cosx) = (sinx+cosx
1. 0 answers
2. asked by Tim
3. 580 views