(cotxsec2x - cotx)/ (sinxtanx +

(cotxsec2x - cotx)/ (sinxtanx + cosx) = sinxprove. i keep getting (if i start from the left side) = cosx instead of sinx please
1. 1 answer
2. asked by Spencer
3. 1,415 views
cotx+tan2x=cotxsec2xprove
1. 1 answer
2. asked by jhon
3. 1,363 views
Determine the derivative for y=tanxcosxa) y'=-sinxtanx + cosxsec^2x b) y'=-sinxtanx + cosxtanx c) y'=cosxsec^2x d) y'=sinx -
1. 2 answers
2. asked by Melinda
3. 674 views
How do I solve this? My work has led me to a dead end.tan(45-x) + cot(45-x) =4 my work: (tan45 - tanx)/(1+ tan45tanx) + (cot45 -
1. 0 answers
2. asked by Jess
3. 729 views
Prove cotx-1/cotx+1 = sec2x - tan2xI prove till cotx-1/cotx+1 =1/1+tanx - tanx/1+tanx
1. 1 answer
2. asked by wang
3. 1,502 views
express this in sinx(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
1. 1 answer
2. asked by linds
3. 1,399 views
Write in terms of cos and sin function.cotx*secx I know cotx = cosx/sinx and sec x= 1/cos x. but how do i solve it?
1. 1 answer
2. asked by Math
3. 565 views
Prove that if y = cotx then dy/dx = - (cscx)^2. Hint: cotx = cosx/sinx
1. 1 answer
2. asked by help me pls
3. 438 views
So I have a math problem where I need to solve an equation for x where x is within (0, 2pi)I have it simplified down to
1. 2 answers
2. asked by Worm
3. 273 views
My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
1. 2 answers
2. asked by Jon
3. 920 views