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(cos^2+6cos x + 9) /
Hi! The question I need help with is 6cos^2x-3 and the directions say to use a double-angle formula to write the expression.
2 answers
asked by
Penny
590 views
Find the volume bounded by r=2-2cos theta and r=-6cos theta
Would this be right 1/2 ∫ [5π/3,π/3] ((-6cos theta)^2 - (2-2cos
1 answer
asked by
Wyatt
303 views
I got this far, but now I'm stuck...please help
6cos^2theta - 5cos(theta) + 1 = 0 6cos^2theta - 5cos(theta) = -1 cos(theta) *
1 answer
asked by
Tara
794 views
-6cos(x)+7=10
1 answer
asked by
logan
242 views
(cos^2+6cos x + 9) / (cos x + 3)
2 answers
asked by
Ann
301 views
If f(x) = 7x^6cos^-1x, find f '(x).
2 answers
asked by
mock
1,263 views
6cos^2(x)-5cos(x)-6
1 answer
asked by
Ashleigh
955 views
integral from 0 to pi of 9+6cos((pi/25)y)+cos^2((pi/25)y)
0 answers
asked by
Noor
903 views
What is the phase shift of y=6cos(6x+pi/2)?
1 answer
asked by
Dwight
871 views
find the indefinite integral of the following f(t)=6cos(3t)+5e^-10t
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asked by
cecelia
330 views