(cos^2+6cos x + 9) /

  1. Hi! The question I need help with is 6cos^2x-3 and the directions say to use a double-angle formula to write the expression.
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    2. Penny asked by Penny
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  2. Find the volume bounded by r=2-2cos theta and r=-6cos thetaWould this be right 1/2 ∫ [5π/3,π/3] ((-6cos theta)^2 - (2-2cos
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    2. Wyatt asked by Wyatt
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  3. I got this far, but now I'm stuck...please help6cos^2theta - 5cos(theta) + 1 = 0 6cos^2theta - 5cos(theta) = -1 cos(theta) *
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    2. Tara asked by Tara
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  4. -6cos(x)+7=10
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    2. logan asked by logan
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  5. (cos^2+6cos x + 9) / (cos x + 3)
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    2. Ann asked by Ann
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  6. If f(x) = 7x^6cos^-1x, find f '(x).
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    2. mock asked by mock
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  7. 6cos^2(x)-5cos(x)-6
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    2. Ashleigh asked by Ashleigh
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  8. integral from 0 to pi of 9+6cos((pi/25)y)+cos^2((pi/25)y)
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    2. Noor asked by Noor
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  9. What is the phase shift of y=6cos(6x+pi/2)?
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    2. Dwight asked by Dwight
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  10. find the indefinite integral of the following f(t)=6cos(3t)+5e^-10t
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    2. cecelia asked by cecelia
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