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(3-4sin^2A)(1-3tan^2A) =(3-tan^2A)(4cos^A-3)

  1. (3-4sin^2a)(1-3tan^2a)=(3-tan^2a)(4cos^2a-3)
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    2. Optional asked by Optional
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  2. (3-4sin^2A)(1-3tan^2A) =(3-tan^2A)(4cos^A-3)
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    2. Shreya asked by Shreya
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  3. (3-4sin^2thita)(1-3tan^A)=(3-tan^2A)(4cos^2A-3)
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    2. Soniya asked by Soniya
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  4. Prove that:(3-4sin^2A) (1-3tan^2A)=(3-tan^2A)(4cos^2A-3)
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    2. Rishabh asked by Rishabh
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  5. Prove that (3-4sin^2A) (1-3Tan^2A)= (3-tan^2A) (4cos^2A-3)
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    2. Alina maharjan asked by Alina maharjan
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  6. 1. 4sin^2x=3tan^2x-12. 8cos^2x-4cos^4x=3 3. 3secx-cosx=2
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    2. Michael asked by Michael
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  7. If sec x = 17/8; verify that 3 - 4sin^2x /4cos^2x -3 = 3- tan^2x / 1-3tan^2x.. I have used x in place of theta. It isn't
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    2. Agile asked by Agile
    3. views icon 959 views
  8. Solve the equation for solutions in the interval 0<=theta<2piProblem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1
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    2. Renee asked by Renee
    3. views icon 1,715 views
  9. Which equation would the table of values represent? 0, 3 pi over 2, 3 pi, 9 pi over 2, 6 pi. 0, 4, 0, -4, 0 (1 point) Responses
    1. answers icon 1 answer
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  10. Write an equation for simple harmonic motion, given that the amplitude equals 4 inches and the period equals 2 seconds and the
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    2. Kayla asked by Kayla
    3. views icon 539 views