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(2xy^2+16x^2y-20xy+8) / (4xy)
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How come when you find the square of the binomial (2x-5y)^2, the answer is 4x^2-20xy+25y^2 (according to my book)? I would think
1 answer
asked by
Sandrine
415 views
If 3xy^3 - 4x = 10y^2, find y ' (x)
a) (4 + 3y^2)/(9xy^2 + 20y) b) (4 - 3y^2)/(9xy^2 - 20y) c) (3 + 4y^2)/(20xy^2 + 9y) d) (3 -
2 answers
asked by
Donna
663 views
(X^3YZ^2-20XY+21X^3)+(15X^3-41X^3YZ^2-3XY)
1 answer
55 views
(X^3YX^2-20XY+21X^3)+(15X^3YZ^2-3XY)
1 answer
47 views
(2xy^2+16x^2y-20xy+8) / (4xy)
1 answer
asked by
christine
513 views
(2x + 5y)(3x^2 - 4xy + 2y^2)
= 6x^3 - 8xy + 4xy^2 + 15x^2y - 20xy^2 + 10y^3
1 answer
asked by
Anonymous
754 views
20xy=? I do not get this at all! Please HELP!
3 answers
asked by
renee
302 views
please i need help factoring these problems....20xy, 36g^2h^2, and 44m^2n
1 answer
asked by
savannah
376 views
Factor the expression 4x^2-20xy+25y^2
into a product of binomials
1 answer
asked by
kozy
566 views
(5x^3y/20xy^5)^4
According to my teacher the answer is x^8/256y^16, but I don't understand how to get there.
1 answer
asked by
Max
761 views
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