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(1-2cos^2ө)/ (sin ө-cosө) + cotө
(1-2cos^2ө)/ (sin ө-cosө) + cotө
how do I simplify this??? Thank-you for your help!
0 answers
asked by
kayla
457 views
I don't understand how to simplify this. Please help!
(1-2cos^2ө)/ (sin ө-cosө) + cotө
0 answers
asked by
Anonymous
467 views
find in degrees the value of Ө in the interval O¡ÜӨ¡Ü 360 for which 2cos^2Ө-cosӨ-1=sin^2Ө
give your answers to 1 decimal
0 answers
asked by
kuri
554 views
I'm confused about how to get the answer of this question.
If cosө=0.2, find the value of: cosө + cos(ө+2¡Ç) +sin(ө+4¡Ç)
0 answers
asked by
Josh
601 views
how would this multiply out
(1/cosө) (Sin^2ө + cos^2ө/cosө * sinө)
2 answers
asked by
kayla
479 views
I don't understand this problem:
(Tanө + cos ө)/ (sec ө + cot ө) so I start off like this: ={(sinө / cos ө)+cosө}{cos ө +
1 answer
asked by
allison
567 views
cosA= 5/9 find cos1/2A
are you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
0 answers
asked by
Anonymous
812 views
What am I doing wrong?
Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
1 answer
asked by
Anonymous
967 views
Determine the solution of the equetion: 2cos x-1=0? 2cos x=0? and 2cos x+1=0?
3 answers
asked by
Miley
495 views
how does 2cos(2x)-2cos(x)sin(x) becomes 2cos(2x)-sin(2x)? Try to explain each step simply.
1 answer
71 views