(1-2cos^2ө)/ (sin ө-cosө) + cotө

  1. (1-2cos^2ө)/ (sin ө-cosө) + cotөhow do I simplify this??? Thank-you for your help!
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    2. kayla asked by kayla
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  2. I don't understand how to simplify this. Please help!(1-2cos^2ө)/ (sin ө-cosө) + cotө
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    2. Anonymous asked by Anonymous
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  3. find in degrees the value of Ө in the interval O¡ÜӨ¡Ü 360 for which 2cos^2Ө-cosӨ-1=sin^2Өgive your answers to 1 decimal
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    2. kuri asked by kuri
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  4. I'm confused about how to get the answer of this question.If cosө=0.2, find the value of: cosө + cos(ө+2¡Ç) +sin(ө+4¡Ç)
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    2. Josh asked by Josh
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  5. how would this multiply out(1/cosө) (Sin^2ө + cos^2ө/cosө * sinө)
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    2. kayla asked by kayla
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  6. I don't understand this problem:(Tanө + cos ө)/ (sec ө + cot ө) so I start off like this: ={(sinө / cos ө)+cosө}{cos ө +
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    2. allison asked by allison
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  7. cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
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    2. Anonymous asked by Anonymous
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  8. What am I doing wrong?Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
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    2. Anonymous asked by Anonymous
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  9. Determine the solution of the equetion: 2cos x-1=0? 2cos x=0? and 2cos x+1=0?
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    2. Miley asked by Miley
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  10. how does 2cos(2x)-2cos(x)sin(x) becomes 2cos(2x)-sin(2x)? Try to explain each step simply.
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    2. views icon 71 views