Is that 2.6M HCl? I will assume so.
Zn + 2HCl ==> ZnCl2 + H2
How many mols H2 is that?
Ptotal = 845 torr
pH2O at 65C = approx 190 torr. You need to look up this value in your text/notes because I've estimated it from some tables I have.
pH2 = 845-190 = about 655 mm or
655/780 = about 0.86 atm
Then use PV = nRT and solve for n = number of mols H2. P is the approx 0.86 (but you use the accurate number), V = 0.728L, T must be in kelvin etc.
Convert mols H2 to mols HCl using the coefficients in the balanced equation. That is ?mols H2 x (2 mols HCl/1 mol H2) = xx.
Then M HCl = mols HCl/L HCl. You have mols and M, solve for L and convert to mL.
Zn+HCl---->ZnCl2+H2
If you measure the total volume of collected gas over water at 65*C to be 728 mL at a total pressure of 845 torr, how many milliliters of 2.6 HCl would be required to produce the correct amount of hydrogen?
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