Did you proof read your post? Probably not. The reaction produces ZnS which is zinc sulfide. (or sulphide). Do you intend to say that 16.2 g Zn reacts? I will assume so. So what is O at 16. Is this forming ZnS or ZnSO4. I will assume ZnS.
a. Zn + S ==> ZnS
b. mols Zn = 16.2/65 = ?
c. Using the coefficients in the balanced equation convert mols Zn to mols S. The equation shows that 1 mol Zn reacts with 1 mol S; therefore, mols Zn = mols S.
Zinc reacts with sulphur to form zinc sulphuric 16.2g.Sample of zinc is reacted with log of sulphur(Zn=65,S=32,o=16)
A)Write a chemical reaction for the reaction
b)Calculate the number of moles of zinc atoms that reacted.
c)Number of moles of sulphur atoms that reacted
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