Assuming zinc is in excess.
18 mL of 6.00 M H2SO4 equals 0.108 mol
From
Zn+H2SO4 -> ZnSO4 + H2
we deduce that 1 mol of H2SO4 produces 1 mol of ZnSO4.
So mass of ZnSO4 produced is 0.108 mol, multiplied by the molecular mass of ZnSO4.
Zinc reacts with 18.0 mL of 6.00 M cold, aqueous
sulfuric acid through single replacement.
a. How much zinc sulfate is produced?
Answer in units of g
1 answer