Zinc fluoride (ZnF2) dissociates according to the following equation:
ZnF2(s) ⇌ Zn2+(aq) + 2F–(aq)
Ksp of this equilibrium is 3.0 × 10–2.
If the concentration of zinc ions (Zn2+) in a solution is measured to be 4.4 × 10–1 M, what is the concentration of the fluoride ions (F–)?
2 answers
Ksp = (Zn^2+)(F^-)^2. You know Ksp and Zn^2+, solve for F^- but this works ONLY i the solution is saturated with ZnF2.
2.6 x 10^-1 hope dis helps
1 answer