Z varies x whole number one all over y square and z is 8 when x is 5 and y is 2.5. Find the constant of proportionality

1 answer

To find the constant of proportionality when the variable \( z \) varies directly with \( \frac{x}{y^2} \), we can express this relationship mathematically as:

\[ z = k \cdot \frac{x}{y^2} \]

where \( k \) is the constant of proportionality.

We are given that \( z = 8 \), \( x = 5 \), and \( y = 2.5 \). First, we need to find \( y^2 \):

\[ y^2 = (2.5)^2 = 6.25 \]

Now, we can substitute the known values into the equation:

\[ 8 = k \cdot \frac{5}{6.25} \]

Next, we calculate \( \frac{5}{6.25} \):

\[ \frac{5}{6.25} = \frac{5}{\frac{25}{4}} = 5 \cdot \frac{4}{25} = \frac{20}{25} = \frac{4}{5} \]

Now our equation becomes:

\[ 8 = k \cdot \frac{4}{5} \]

To find \( k \), we isolate it by multiplying both sides by the reciprocal of \( \frac{4}{5} \):

\[ k = 8 \cdot \frac{5}{4} = 10 \]

So, the constant of proportionality \( k \) is:

\[ \boxed{10} \]