time on bus = (5/60)hr
= (5/60)(60) = 5 minutes
so he walked for 20 inutes
20 minutes (1 hour/60 min) = (1/3)hr
2 km/(1/3)hr = 6 km/hr
Yumi walked 2 km to a bus stop to catch the bust to school. The bus arrived straight away and averaged 60km/h for the 5km trip.
Yumi's total travelling time was 25 minutes.
at what average speed did Yumi walk to the bus stop?
The answer is 6, but the only thing I could think of to get to there is 60km/h / 5km trip
is 12mins for the bus trip, which leaves 13 minutes left, and dividing that by 2 km to get the km/h, which would equal 6.5.
2 answers
time on bus = distance / rate
= 5km/60 km/h
= .08333 hrs = 5 minutes
(you had distance = rate/distance !)
that leaves 20 minutes or 1/3 hour for walking the 2 km
rate of walking = 2/(1/3) = 2(3/1)
= 6 km/h
= 5km/60 km/h
= .08333 hrs = 5 minutes
(you had distance = rate/distance !)
that leaves 20 minutes or 1/3 hour for walking the 2 km
rate of walking = 2/(1/3) = 2(3/1)
= 6 km/h