To find the length of \( LS \), we will need to use the Law of Cosines. However, since you have provided only the lengths \( YS \) and \( YL \), I will make an assumption that these lengths represent the distances from a common point \( Y \) to points \( S \) and \( L \). To find \( LS \), I'll need an angle \( \angle SYL \) or additional information on how these points are arranged.
Assuming the points are arranged in a triangle as follows: \( Y \) at the apex, with segment lengths as given, the formula we will use is:
\[ LS^2 = YS^2 + YL^2 - 2 \cdot YS \cdot YL \cdot \cos(\angle SYL) \]
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Identify the lengths:
- \( YS = 6.3 \) km
- \( YL = 15.4 \) km
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Find the angle \( \angle SYL \): Since you didn't provide \( \angle SYL \), we cannot compute \( LS \).
If you have \( \angle SYL \), you can substitute it into the formula above (in degrees or radians) to find \( LS \).
- If you provide an angle, we can continue: As an example, assume \( \angle SYL = 60^\circ \):
\[ LS^2 = (6.3)^2 + (15.4)^2 - 2 \cdot (6.3) \cdot (15.4) \cdot \cos(60^\circ) \]
Since \( \cos(60^\circ) = 0.5 \):
\[ LS^2 = 39.69 + 237.16 - 2 \cdot (6.3) \cdot (15.4) \cdot 0.5 \]
Calculating the second product:
\[ LS^2 = 39.69 + 237.16 - (6.3 \cdot 15.4) \ = 39.69 + 237.16 - 48.54 \]
Calculating \( LS^2 \):
\[ LS^2 = 39.69 + 237.16 - 48.54 \ = 228.31 \]
Now take the square root:
\[ LS = \sqrt{228.31} \approx 15.1 \text{ km} \]
Thus, if \( \angle SYL = 60^\circ \), \( LS \) would be approximately \( 15.1 \) km. Please provide the actual angle or additional details for a specific computation.