Your town is installing a fountain in the main square. If the water is to rise 26 m (85.3 feet) above the fountain, how much pressure must the water have as it moves slowly toward the nozzle that sprays it up into the air? Assume atmospheric pressure equal to 100,000 Pa.

3 answers

it has to gain sufficent force to rise which equals the weight of the height of the water.

We will calculate in gauge pressure...

pressure=force/area= density*area*height*g/area= density*g*height

height = 26m
density= 1.04E6kg/m^3
g= 9.8N/kg

so calcualate pressure, it ought to be about three atmosphers, or 3E5Pa
373000
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