Period=2PI sqrt(l/g)
with calculus..
dPeriod/dl=2PI 1/(2sqrtl/g)
dl=dperiod sqrt(l/g) *PI
dperiod=95.6/24*3600 second per second
change in length=sqrt(l/g)*PI*95.6/24*3600
= sqrt(.9930/9.81)*PI*95.6/24*3600
= I get = 0.00110594656 m
check my math.
Your grandfather clock’s pendulum has a length of 0.9930 m. If the clock loses 95.6 seconds per day, by how many millimeters should you adjust the length of the pendulum?
2 answers
snd dfmd