Let's solve the system of equations step by step.
We have two equations:
- \( x + y = 34 \) (Equation 1)
- \( x - y = 12 \) (Equation 2)
We can solve these equations using the elimination or substitution method. Here, we'll use the elimination method by adding the two equations together.
Adding Equation 1 and Equation 2:
\[ (x + y) + (x - y) = 34 + 12 \]
This simplifies to:
\[ 2x = 46 \]
Now, divide both sides by 2:
\[ x = 23 \]
Now that we have \( x \), we can substitute it back into Equation 1 to find \( y \):
\[ 23 + y = 34 \]
Subtract 23 from both sides:
\[ y = 34 - 23 \] \[ y = 11 \]
Thus, the two numbers are \( 23 \) and \( 11 \).
So the answer is 23 and 11.