The probability of the first game being against the Snakes is 6/60 = 1/10.
The probability of the second game being against the Snakes is 5/59 (since there are 5 games left against the Snakes and 59 total games remaining).
Therefore, the probability that both games are against the Snakes is (1/10) * (5/59) = 5/590.
Your employer is offering free tickets for two baseball games. They play
60
60 home games and
6
6 of them are against the Snakes. The tickets are randomly given out. What is the probability that both are games are against the Snakes? Write your answer as a fraction. You do not need to simplify.
1 answer