The probability that the first game is against the Snakes is $\frac{7}{55}$ and the probability that the second game is also against the Snakes is $\frac{6}{54}$ (since there will be one less home game left after the first game against the Snakes).
Therefore, the probability that both games are against the Snakes is:
$$\frac{7}{55} \times \frac{6}{54} = \frac{42}{2970}$$
So the probability is $\frac{42}{2970}$.
Your employer is offering free tickets for two baseball games. They play 55 home games and 7 of them are against the Snakes. The tickets are randomly given out. What is the probability that both are games are against the Snakes? Write your answer as a fraction. You do not need to simplify.
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