Your employer is offering free tickets for two baseball games. They play 53 home games and 8 of them are against the snakes the tickets are randomly given out. What are the probability that both games are against the snakes? Write your answer as a fraction. You do not need to simplify.

Answer 1

The probability of randomly selecting a game against the snakes is $\frac{8}{53}$.

Therefore, the probability of selecting two games against the snakes is
$\frac{8}{53} \times \frac{8}{53} = \frac{64}{2809}$.