The probability of the first game being against the Snakes is 8 out of 53, and the probability of the second game being against the Snakes is 7 out of 52 (since there was already one game against the Snakes).
Therefore, the probability that both games are against the Snakes is (8/53)*(7/52).
Answer: 56/2756
Your employer is offering free tickets for two baseball games. They play 53 home games and 8 of them are against the Snakes. The tickets are randomly given out. What is the probability that both are games are against the Snakes? Write your answer as a fraction. You do not need to simplify what is the answer
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