Your employer is offering free tickets for two baseball games. They play 53 home games and 8 of them are against the Snakes. The tickets are randomly given out. What is the probability that both are games are against the Snakes? Write your answer as a fraction. You do not need to simplify.

Answer 1

The probability of the first ticket being for a game against the Snakes is $\frac{8}{53}$.

Since the tickets are given out randomly, the probability of the second ticket also being for a game against the Snakes is also $\frac{8}{53}$.

Therefore, the probability that both tickets are for games against the Snakes is $\frac{8}{53} \times \frac{8}{53} = \frac{64}{2809}$.