To conduct the hypothesis test and calculate the p-value, we need to define our null and alternative hypotheses based on the given claim.
Let's assume the null hypothesis \( H_0 \) is that the population proportion \( p \) is equal to 0.76. The alternative hypothesis \( H_a \) is that the population proportion \( p \) is greater than 0.76.
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Define the null and alternative hypotheses:
- \( H_0: p = 0.76 \)
- \( H_a: p > 0.76 \)
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Sample details:
- Sample size \( n = N \) (please replace \( N \) with the actual size)
- Number of successes \( x = 497 \)
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Binomial Distribution: Since the binomial distribution is used, if \( H_0 \) is true, we will have a binomial distribution with parameters \( n \) and \( p = 0.76 \).
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Calculate the p-value:
- The p-value represents the probability of observing at least 497 successful observations when the population proportion is 0.76: \[ \text{p-value} = P(X \geq 497) = 1 - P(X < 497) \]
- Here, \( P(X < 497) \) is the cumulative probability of getting fewer than 497 successes, which can be calculated using the binomial distribution.
You would use a binomial calculator or software to find this probability. Assuming you plug in the numbers correctly:
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Interpret the p-value:
- If the p-value is small (typically less than the significance level, say 0.05), that means we have evidence to reject \( H_0 \).
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Decision:
- If the p-value is less than or equal to the significance level, reject the null hypothesis.
- If the p-value is greater than the significance level, fail to reject the null hypothesis.
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Final conclusions: Based on the results:
- If we reject \( H_0 \), it would imply that there is sufficient evidence to support the claim that the population proportion is greater than 0.76.
- If we fail to reject \( H_0 \), it would imply that there is not sufficient evidence to support this claim.
Since I don't have the values for \( N \) (sample size), I cannot compute the exact p-value or make precise conclusions. Please provide the sample size \( n \) (the total number of observations), and I can help you further with the calculations.