I posted the answer then re-read the problem and saw I had not included energy to remove that 50 mL H2O at the boiling point. Therefore, I deleted that post. Here is the complete answer.
energy to melt ice + energy to raise melted ice to 100 from zero C + energy to raise 100 g H2O initially at zero to 100 + energy to evaporate 50 mL (which I assume is 50 g but you can look up the density and change that 50 mL to mass).
Ice mass = volume x density
If you need to convert 50 mL water @ 100, then mass water = volume x density.
q = [mass ice x heat fusion] + [mass melted ice x specific heat liquid water x (Tfinal-Tinitial)] + [mass liquid water initially x (Tfinal-Tinitial)] + [mass H2O at 100 x heat vaporization]
Here Tfinal is 100 and Tinitial is 0.
you wish to combine two samples, one sample contains is solid water at 0 degree celsius.The other sample contains liquid water at 0 degree celsius,you want to combine both raise the temperature to 100 degree celcius but boil off only 50 ml to gas phase keep the rest as liquid.How much energy is neededfor this?Both is 100ml(iceand liquid water)
here liquid water initial temperatureis 0 degree celcius.final is 100
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