Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. Is it significant?
You wanted to test whether the cereal boxes made by your plant conform to the requirement that they contain 12 oz cereal. You wish to test at the 99 percent significance level, and you sample 100 boxes, finding the mean x as 11.85, standard deviation s is 0.5. Do your cereal boxes meet the standard?
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