Hello! You have the correct formula: F= mgsin theta
Now plug in those values!
m=66 kg
g= 9.8 m/s^2
theta (angle)= 30 degrees
Normal Force= 66 * 9.8 * 0.5
Normal Force= 33 * 9.8
Normal Force= 323.4 Newtons
Then, use F=coefficient of friction * Normal Force
F= 0.35 * 323.4
F=113.19 Newtons which rounds to 113.2 N
Hope this helps!
You want to push a 66-kg box up a 30° ramp. The coefficient of kinetic friction between the ramp and the box is 0.35. With what magnitude force parallel to the ramp should you push on the box so that it moves up the ramp at a constant speed?
N
Physics - bobpursley, Thursday, February 16, 2012 at 5:04pm
You have to overcome friction and gravity
gravity down the plane:mg*SinTheta
friction: mg*mu*cosTheta
I know i posted this before earlier sorry about that but I really need help with it because its not working out please help
1 answer