You want to make an investment in a continuously compounding account over a period of two years. What interest rate is required for your investment to double in that time period? Round the logarithm value and the answer to the nearest tenth.

Answer 1

suppose we invest $1.00

2 = 1 e^(2r)
ln 2 = 2r lne , but lne = 1
2r = ln2
r = ln2/2 = appr .34657..

= appr 34.66%

nice if you can get it