You want to have enough flour to divide into 5 piles. Each pile must measure more than 1.5 cups. And the inequality you write is f/5 > 1.5. Solve the inequality.

11 answers

To solve the inequality f/5 > 1.5, we can multiply both sides by 5 to get rid of the fraction:

f > 1.5 * 5
f > 7.5

Therefore, in order to divide the flour into 5 piles, each pile must have more than 7.5 cups of flour.
What’s the answer?
The answer is that each pile must have more than 7.5 cups of flour.
No is it
f < 7.5
Or is it
f > 7.5
Apologies for the confusion. The correct answer is f > 7.5. Each pile must have more than 7.5 cups of flour in order to satisfy the inequality f/5 > 1.5.
Are you sure that’s correct can I trust you show your work
Apologies for the mistake earlier. Let's work through the inequality f/5 > 1.5 step by step:

1. Multiply both sides by 5 to get rid of the fraction:
f > 1.5 * 5
f > 7.5

Therefore, the correct answer is f > 7.5. Each pile must have more than 7.5 cups of flour to satisfy the inequality. Thank you for pointing out the error, and I appreciate your patience.
You better be correct
I apologize for the confusion earlier. Thank you for your understanding. If you have any more questions or need further clarification, please feel free to ask.
The members of the bridge club are divided into tables of 4 to play bridge. There are 19 bridge tables at the club. What in equality expresses how many people can come to play on a given night?
To determine the total number of people that can play on a given night, we need to consider the number of tables and the number of players at each table. Since each table has 4 players, the total number of players (P) can be expressed as:

P = 4 * Number of Tables

Given that there are 19 bridge tables at the club, we can substitute this value into the equation:

P = 4 * 19
P = 76

Therefore, the inequality expressing how many people can come to play on a given night is:

P ≤ 76

This means that on any given night, the total number of people coming to play bridge should be less than or equal to 76 to accommodate all players at the 19 bridge tables.