Asked by John Yi
You walk 55 m to the north, then turn 60° to your right and walk another 46 m. How far are you from where you originally started?
Can someone help me with this question please? I have tried Pythagorean but it did not work. thank
Can someone help me with this question please? I have tried Pythagorean but it did not work. thank
Answers
Answered by
Henry
D = 55m@90o + 46m@30o,CCW from 0.
X = 46*cos30 = 39.84 m..
Y = 55 + 46*sin30 = 78 m.
D^2 = (39.84)^2 + (78)^2 = 7671.2
D = 87.6 m.
X = 46*cos30 = 39.84 m..
Y = 55 + 46*sin30 = 78 m.
D^2 = (39.84)^2 + (78)^2 = 7671.2
D = 87.6 m.
Answered by
The Spicelings
Henry's answer would be correct except it should remain 60 degrees; not 30 degrees.
Answered by
Hoor
Thank you for replying The Spicelings after henrys answer by 8 years
Answered by
V
Not Hoor responding almost half a year later... LOL this thread is making me laugh. Thanks for the answer
Answered by
Bruh
Also, if you go North and turn 60 degrees to the right you are now at a standard angle (angle from the positive x-axis) of 30 degrees. So for anyone searching up this question, yes, you do use 30 degrees not 60 so The Spicelings is wrong.
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