D = 55m@90o + 46m@30o,CCW from 0.
X = 46*cos30 = 39.84 m..
Y = 55 + 46*sin30 = 78 m.
D^2 = (39.84)^2 + (78)^2 = 7671.2
D = 87.6 m.
You walk 55 m to the north, then turn 60° to your right and walk another 46 m. How far are you from where you originally started?
Can someone help me with this question please? I have tried Pythagorean but it did not work. thank
5 answers
Henry's answer would be correct except it should remain 60 degrees; not 30 degrees.
Thank you for replying The Spicelings after henrys answer by 8 years
Not Hoor responding almost half a year later... LOL this thread is making me laugh. Thanks for the answer
Also, if you go North and turn 60 degrees to the right you are now at a standard angle (angle from the positive x-axis) of 30 degrees. So for anyone searching up this question, yes, you do use 30 degrees not 60 so The Spicelings is wrong.