You use scale factor of 3/4

to create a dilated circle with a radius of 9 inches. What is the radius of the original circle

1 answer

To find the radius of the original circle before dilation, you can use the scale factor. The relationship between the original radius \( r \) and the dilated radius \( r' \) is given by:

\[ r' = k \cdot r \]

where \( k \) is the scale factor. In this case, the dilated radius \( r' = 9 \) inches and the scale factor \( k = \frac{3}{4} \).

Rearranging the formula to solve for \( r \), we get:

\[ r = \frac{r'}{k} \]

Substituting the known values:

\[ r = \frac{9 \text{ inches}}{\frac{3}{4}} \]

To divide by a fraction, you multiply by its reciprocal:

\[ r = 9 \text{ inches} \times \frac{4}{3} \]

Calculating this:

\[ r = 9 \times \frac{4}{3} = \frac{36}{3} = 12 \text{ inches} \]

So, the radius of the original circle is 12 inches.