To find the probability of all four coins landing on tails, we can consider that each coin has two possible outcomes: heads (H) or tails (T).
The probability of landing on tails for each coin is \( \frac{1}{2} \).
Since the tosses of the coins are independent events, we can multiply the probabilities:
\[ P(\text{all tails}) = P(\text{tails for penny}) \times P(\text{tails for nickel}) \times P(\text{tails for dime}) \times P(\text{tails for quarter}) \]
\[ = \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \]
\[ = \left(\frac{1}{2}\right)^4 = \frac{1}{16} \]
Thus, the probability of all four coins landing on tails is \( \frac{1}{16} \).
The correct answer is:
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