You throw a water balloon hoping to hit your sibling. You throw it at an angle of 21.0° at 5.50 m/s. It ends up leaving your hand at a height of 1.70 m above the ground. It completely misses your sibling and breaks on the ground. How far did the water balloon travel?

1 answer

in the vertical:
hf=hi+vi'*t-4.0t^2
0=1.7+5.5*sin21*t-4.9t^2
it is a quadratic equation solve for time t.

Horizontal distance:
distance=5.5cos21*t

Lucky kid