Dx = Vo^2*sin(2A)/g = 44. m.
Vo^2*sin(68)/9.8 = 44.
Vo^2*0.0946 = 44.
Vo^2 = 465.1.
Vo = 21.6 m/s. at 34o below the hor.
Xo = Vo*Cos A = 21.6*Cos34 = 17.9 m/s.
Dx = 17.9*T = 44.
T = 2.46 s. = Time in air.
You throw a snowball at an angle of 34.0° below the horizontal from the roof of a building that is 74.0 m above flat ground. The snowball hits the ground a distance of 44.0 m from the base of the building. Assume free fall with up as positive, and use g = 9.80 m/s2.
how long the projectile remain in the air?
what is the initial speed of the snowball?
1 answer
1 answer