your equation
h= -16t^2+20t+6
is modelled by a parabola which opens downwards.
Find the vertex of this parabola by the means that you learned, and you will have both answers.
you throw a ball up in the air. given the function
h=-16t^2+20t+6
1)when does the ball reach it maximum height? and
2)what is the ball's maximum height?
2 answers
I assume you are not a calculus student.
This is a parabola. Looking at the zeroes
0=-16t^2+20t+6
( 8t+2)(-2t+3)=0
t=-1/4, t=3/2
because the maximum will occure at the halfway point between two zeroes, then
half way: (1.5+.25)/2 - 1.5
=1.5-(1.75)/2=
t=.625 is the location of the max
for max height, plug that t into the original equation.
This is a parabola. Looking at the zeroes
0=-16t^2+20t+6
( 8t+2)(-2t+3)=0
t=-1/4, t=3/2
because the maximum will occure at the halfway point between two zeroes, then
half way: (1.5+.25)/2 - 1.5
=1.5-(1.75)/2=
t=.625 is the location of the max
for max height, plug that t into the original equation.
1 answer