(1/2)mv^2 + mgh = (1/2) mv^2+ mgh, m cancels, does not matter
(1/2) v^2 + 0 = (1/2) * 625 + 9.81*15 solve for v
You throw a 3.00-N rock vertically into the air from ground level. You observe that when it
is 15.0 m above the ground, it is traveling at 25.0 m/s upward. Use the work–energy theorem
to find
a. the rock’s speed just as it left the ground
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