distance N=1/2 *1*10^2=50m
head west velocity=10*1=10m/s
distance w=10m/s*20 sec=200m
displacement: sqrt(200^2+50^2)
direction approximately NW again
avg velocity(magnitude)=displacement/tim = displacementabove/30sec
You take a trip in your car. Starting from rest, you accelerate at 1.00 m/s2 for 10.0 s, heading north. You then stop accelerating and immediately head west at a constant speed for an additional 20.0 s, at which point, you crash into a building coming to an instant stop. At the instant before impact, your average velocity is:
Answer: 6.87 m/s approximately north-west
BUT I am not sure HOW to get down to this answer so please explain !
Thanks !
1 answer
1 answer