You spot a plane that is 1.63 km north, 2.3 km east, and at an altitude 5.2 km above your position.

Question

1) At what angle from due north (in the horizontal plane) are you looking?

( ) °E of N

2) Determine the plane's position vector (from your location) in terms of the unit vectors, letting ihatbold be toward the east direction, jhatbold be toward the north direction, and khatbold be in vertically upward.

( ) km ihatbold

3) ( ) km jhatbold

Answer 1

On this, first compute the bearing based on N. Theta=arctan(E/N). If it had been some west, or S distance, you would use a negative.
Positon vector, you have the N, E vectors, and now, then k= 5.2

so you have N, E, k

Answer 2

1. Tan A = X/Y = 2.3/1.63 = 1.41104.
A =