You spin a spinner that is divided into 6 equals parts once and roll the number cube once. Find the probability that the spinner stops on the same number that you roll the number cube?

Answer 1

Wherever the spinner stops, the cube has to match that
so prob = (1)(1/6) = 1/6

or, the long way:

it could be 11 22 33 44 55 66

prob = (1/6)(1/6) + (1/6)(1/6) + ... (1/6)(1/6)
= 1/36 + 1/36+ .. + 1/36 , for 6 terms
= 6(1/36) = 1/6