you spent 1/2 of your money on a camera and 18 on a radio. the camera cost $120 more than the radio. How much money did you start with?
3 answers
Do you mean "1/8" on a radio?
c = 240, r = 60, x = 480
he started with $480
he spent $60 on the radio and $240 on the camera.
he started with $480
he spent $60 on the radio and $240 on the camera.
x = starting cash
the camera: z = (1/2)x
the radio:y = (1/8)x
the camera is $120 more than the radioz = y + 120
y + 120 = (1/2)x
y = (1/8)x
put the system of linear equations into standard form
0.5x - y = 120
0.125x - y = 0
answer:
starting cash = $320
camera = $160
radio = $40
the camera: z = (1/2)x
the radio:y = (1/8)x
the camera is $120 more than the radioz = y + 120
y + 120 = (1/2)x
y = (1/8)x
put the system of linear equations into standard form
0.5x - y = 120
0.125x - y = 0
answer:
starting cash = $320
camera = $160
radio = $40