Initial momentum = 0.035 * 225
final momentum = ( 0.035 + 15 ) * v
final = initial, solve for v
Friction force = 0.18 * ( 0.035 + 15 ) * 0.81 Newtons
Friction force * distance = initial Ke = (1/2) * ( 0.035 + 15 ) v^2
solve for distance
You shoot a 0.035-kg bullet moving at 225.0 m/s into a 15.00-kg block initially at rest on an icy pond.
Determine the velocity of the bullet-block combination.
The coefficient of friction between the block and the ice is 0.18. How far would the block slide before stopping?
1 answer