There are 6 possible outcomes for the first roll and 5 possible outcomes for the second roll.
Out of the 6 possible outcomes for the first roll, 3 are even (2, 4, 6).
If the first roll is even, then there are 5 possible outcomes for the second roll, but we want to exclude the outcome of rolling a 2. Therefore, there are 4 favorable outcomes.
So the probability of rolling an even number on the first roll and then not rolling a 2 on the second roll is:
3/6 * 4/5 = 2/5
Therefore, P(even, then not 2) = 2/5.
You roll a number cube twice. Find P(even, then not 2). Write the probability as a fraction in simplest form.
Only need the math.
5 answers
A number cube is rolled 450 times. The number 3 comes up 67 times.
a. What is the theoretical probability of rolling a 3? Write your answer as a fraction in simplest form.
b. What is the experimental probability of rolling a 3? Write your answer as a fraction in simplest form.
a. What is the theoretical probability of rolling a 3? Write your answer as a fraction in simplest form.
b. What is the experimental probability of rolling a 3? Write your answer as a fraction in simplest form.
a. The theoretical probability of rolling a 3 on a number cube is 1/6, or one out of six possible outcomes. Therefore, the theoretical probability of rolling a 3 is 1/6.
b. The experimental probability of rolling a 3 is found by dividing the number of times a 3 came up in the experiment (67) by the total number of rolls (450):
67/450 = 0.149 or approximately 15/100
Therefore, the experimental probability of rolling a 3 is 15/100, which can be simplified to 3/20.
b. The experimental probability of rolling a 3 is found by dividing the number of times a 3 came up in the experiment (67) by the total number of rolls (450):
67/450 = 0.149 or approximately 15/100
Therefore, the experimental probability of rolling a 3 is 15/100, which can be simplified to 3/20.
You mix the letters M, A, T, H, E, M, A, T, I, C, A, and L thoroughly. Without looking, you draw one letter. Find the probability P(A). Write the probability as:
a. a fraction in simplest form
b. a decimal
c. a percent
a. a fraction in simplest form
b. a decimal
c. a percent
a. There are 12 letters in total, and only 2 of them are A's. Therefore, the probability of drawing an A is 2/12, which simplifies to 1/6.
b. 1/6 as a decimal is approximately 0.1667 (rounded to four decimal places).
c. 1/6 as a percent is approximately 16.67%.
b. 1/6 as a decimal is approximately 0.1667 (rounded to four decimal places).
c. 1/6 as a percent is approximately 16.67%.