There are 36 possible outcomes. How many of these are even and not 2?
Well, of the 36 outcomes, half are even and half are odd. But you want even≠2, so throw out 1,1. That leaves just 17/36
Just to be sure, list all possible successes:
13 15
22 24 26
31 33 35
42 44 46
51 53 55
62 64 66
Looks like P(even≠2) = 17/36
You roll a number cube twice. Find P (even, then not 2). Write the probability as a fraction in simplest form. I'm fully clueless to the answer to this question. Can someone please help me out? Thanks Very Much and need the answer A.S.A.P!
1 answer