Since each roll of the dice is independent of the other, the probability of rolling a three on the first roll is 1/6, and the probability of rolling a four on the second roll is also 1/6.
Therefore, the probability of rolling a three on the first roll and a four on the second roll is (1/6) * (1/6) = 1/36.
You roll a fair six sided dice twice what is the probability of rolling a three on the first row and a fall on the second row?
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