You randomly select a card from a​ 52-card deck. Find the probability of selecting a 4 or a 9.

1 answer

In a standard 52-card deck, there are 4 cards of each rank (one for each suit: hearts, diamonds, clubs, and spades).

To find the probability of selecting either a 4 or a 9, we first count the number of favorable outcomes:

  • There are 4 cards that are 4s.
  • There are 4 cards that are 9s.

So, the total number of favorable outcomes for selecting a 4 or a 9 is:

\[ 4 , (\text{4s}) + 4 , (\text{9s}) = 8 \]

Now, the total number of possible outcomes when drawing a card from the deck is 52.

The probability \( P \) of selecting a 4 or a 9 is given by the formula:

\[ P(\text{4 or 9}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{8}{52} \]

This can be simplified:

\[ P(\text{4 or 9}) = \frac{2}{13} \]

Therefore, the probability of selecting a 4 or a 9 from a 52-card deck is \( \frac{2}{13} \).