You pushed a 1 kg box on floor where= 0.3. If the force you applied was 5 N, will the box move?

Question

m = 1kg
u= 0.3
Fapp= 5 N

Ff= (0.3)(1) (9.81)
Ff = 2.943 N

So therefore the box would move because the frictional force is less than the applied force.

Did I answer this correctly?

Answer 1

Lena, you answered the question right. Good job. The force of friction F(f) = (mew)N. You set up the problem correctly.

One thing to keep in mind is that the applied force might not necessarily be directly opposite the frictional force. The box could be pushed at an angle, making the problem much more complicated.

Answer 2

Oh ok. Thanks :)