You push a 250 kg desk with a force of 800N. The coefficient of friction is 0.2. What is the acceleration of the desk?

Answer 1

Remember the equation: deltaF = ma
In this case delta F is the force applied(800N)-Force of friction.

Now we need to find out the force of friction(Ff). We can do this through the equation Ff=uN.
u is given(.2)
N(the normal force)opposes the downward force of the desk(mg)250*9.81.
Thus Ff=.2*250*9.81=490.5

Back to the original equation, deltaF=ma. now all we do is plug in the values and solve for a.

800-490.5=250a
309.5/250=a
1.24=a

theres your answer, hope i helped

Answer 2

Omer is correct. Thanks for helping, Omer