energy stored in spring = (1/2) k x^2
= (1/2)(100)(.04)
work done by friction
= mu m g *d
so
50*.04 = .2 * 1 *9.81* d
solve for d
You push a 1kg block against a spring with spring constant k = 100 Nmon a horizontal table top. The spring is compressed to 0.2m away from its relaxed length, and then the block is released. If the horizontal table top has a
coefficient of kinetic friction of 0.2, how much further past the end of the spring does the block go before coming to rest?
1 answer