You plan to throw stones by using a sling of length 0.6 m which you whirl over your head. Suppose you wish to throw a stone a distance of 32 m. What must be the centripetal acceleration of the stone just before its release if it is to reach this distance? Assume that the release height is 2.2 m.

Answer 1

time it takes to fall 2.2m
h=1/2 a t^2 solve for t.

distance it goes..
d=vi*t solve for vi.

Now, acceleration= m v^2/r